3x^2-40=7x

Solution for 3x^2-40=7x equation:

3x^2-40=7x

We move all terms to the left:

3x^2-40-(7x)=0

a = 3; b = -7; c = -40;
Δ = b2-4ac
Δ = -72-4·3·(-40)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-23}{2*3}=\frac{-16}{6}
=-2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+23}{2*3}=\frac{30}{6}
=5
$